3x^2-7x+20=x-4

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Solution for 3x^2-7x+20=x-4 equation: 



3x^2-7x+20=x-4

We move all terms to the left:

3x^2-7x+20-(x-4)=0

We get rid of parentheses

3x^2-7x-x+4+20=0

We add all the numbers together, and all the variables

3x^2-8x+24=0

a = 3; b = -8; c = +24;
Δ = b2-4ac
Δ = -82-4·3·24
Δ = -224
Delta is less than zero, so there is no solution for the equation

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